Derivatives · Thu, Nov 5, 2026

ddx(ln⁡(8x+6))=  ?\frac{d}{dx}\left(\ln(8x + 6)\right) = \;?

Answer: 88x+6\frac{8}{8x + 6}

  1. Use the chain rule: differentiate the outer function, leave the inside alone, then multiply by the derivative of the inside.

    ddxf(u)=f′(u)⋅u′\frac{d}{dx} f(u) = f'(u) \cdot u'
  2. The inside function and its derivative are

    u=8x+6,u′=8u = 8x + 6,\quad u' = 8
  3. The derivative of the outside function, in terms of u, is

    dduln⁡u=1u\frac{d}{du}\ln u = \frac{1}{u}
  4. So the answer is

    ddx(ln⁡(8x+6))=88x+6\frac{d}{dx}\left(\ln(8x + 6)\right) = \frac{8}{8x + 6}
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