Derivatives · Wed, Nov 4, 2026

ddx(−5x6+5x+8x8)=  ?\frac{d}{dx}\left(-5x^{6} + 5x + 8x^{8}\right) = \;?

Answer: −30x5+64x7+5-30x^{5} + 64x^{7} + 5

  1. Apply the power rule to each term: bring down the exponent and subtract 1 from it. A constant has derivative 0.

    ddx(axn)=anxn−1\frac{d}{dx}\left(a x^n\right) = a n x^{n-1}
  2. Differentiate this term.

    ddx(−5x6)=−30x5\frac{d}{dx}\left(-5x^{6}\right) = -30x^{5}
  3. Differentiate this term.

    ddx(5x)=5\frac{d}{dx}\left(5x\right) = 5
  4. Differentiate this term.

    ddx(8x8)=64x7\frac{d}{dx}\left(8x^{8}\right) = 64x^{7}
  5. So the answer is

    ddx(−5x6+5x+8x8)=−30x5+64x7+5\frac{d}{dx}\left(-5x^{6} + 5x + 8x^{8}\right) = -30x^{5} + 64x^{7} + 5
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