Algebra · Tue, Nov 3, 2026

Answer: $-13, 1$

1. Read off a, b and c from ax² + bx + c = 0.

   $$a = 1,\quad b = 12,\quad c = -13$$

2. Work out the discriminant, b² − 4ac.

   $$b^2 - 4ac = 12^2 - 4(1)(-13) = 196$$

3. Put the values into the quadratic formula.

   $$x = \frac{-12 \pm \sqrt{196}}{2(1)}$$

4. Simplify the square root.

   $$x = \frac{-12 \pm 14}{2}$$

5. So the answer is

   $$x = -13, 1$$